Question

How many moles are in 83.1g of CaBr2​

Answer 1

0.416 mol CaBr₂

General Formulas and Concepts:

Chemistry - Atomic Structure

• Reading a Periodic Table
• Using Dimensional Analysis

Step-by-step explanation:

Step 1: Define

83.1 g CaBr₂

Step 2: Identify Conversions

Molar Mass of Ca - 40.08 g/mol

Molar mass of Br - 79.90 g/mol

Molar Mass of CaBr₂ - 40.08 + 2(79.90) = 199.88 g/mol

Step 3: Convert

`83.1 \ g \ CaBr_2((1 \ mol \ CaBr_2)/(199.88 \ g \ CaBr_2) )` = 0.415749 mol CaBr₂

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

0.415749 mol CaBr₂ ≈ 0.416 mol CaBr₂