Question

Find 2 consecutive even numbers such that the sum of the

greater number and twice the smaller number is 44.

Answer 1

14, 16

Explanation:

Let the consecutive even numbers be (2x) and (2x+ 2)

Twice the smaller number = 2*2x = 4x

Sum = 44

4x + 2x + 2 = 44

Combine like terms

6x + 2 = 44

Now, subtract 2 from both sides

6x = 44 -2

6x = 42

Divide both sides by 6

x = 42/6

x = 7

2x = 2*7 =14

2x + 2 = 2*7 + 2

= 14 + 2

= 16

`\sf \boxed{\text{\bf Two consecutive even numbers are 14,16}}`

Answer 2

14,16

Explanation:

Let x be the first even number.

Let y be the 2nd even number.

Given, y - x = 2 (Since they are 2 consecutive even numbers.)

rearranging the equation: y = x+2 (equation 1)

Also given,

`y+2x=44\\` (equation 2)

Now we can substitute equation 1 into equation 2 to find x.

`x+2+2x = 44\\3x+2 = 44\\3x = 44-2\\3x=42\\x = (42)/(3) \\x = 14`

Given the smaller even number x, is 14, we will substitute x into equation1 to find y, the bigger even number.

y = 14+2

= 16

Therefore the 2 numbers are 14 and 16.