Answer:
a)
![\huge\boxed{\sf Area\ of\ Parallelogram = 6\ ft.\²}](https://img.qammunity.org/2021/formulas/mathematics/college/nqy0iz1o9v6o1bvzped9jfj8ahegzz4ic3.png)
b)
![\huge\boxed{\sf Area\ of\ the\ equal\ triangles = 3\ ft.\²}](https://img.qammunity.org/2021/formulas/mathematics/college/890w13ybx21fwx51qv4ligy4prq69bi8en.png)
Explanation:
Part A:
Area of Parallelogram = Base * Height
Where Base = 8 ft. and Height = 3/4 ft.
Area of Parallelogram = 8 * 3/4
Area of Parallelogram = 2 * 3
Area of Parallelogram = 6 ft.²
![\rule[225]{225}{2}](https://img.qammunity.org/2021/formulas/chemistry/middle-school/ri1osubq0ul0fyszs3s2hvchlv85n22xxb.png)
Part B:
We can divide the parallelogram into two equal triangles by drawing a diagonal AC or BD. This would create two congruent triangles having an equal area.
Area of the equal triangles = Area of parallelogram / 2
Area of the equal triangles = 6 / 2
Area of the equal triangles = 3 ft.²
![\rule[225]{225}{2}](https://img.qammunity.org/2021/formulas/chemistry/middle-school/ri1osubq0ul0fyszs3s2hvchlv85n22xxb.png)
Hope this helped!
~AH1807