Question

Given that avb=2/a(3/2-b)
If ab=-2/3
solve for b in terms of a.

Answer 1

`\overline{ \underline{\boxed{b = ((9 - 2a))/(6) }}}`

Explanation:

`if \: a \: \overline{ \underline{ \boxed{ \infty }}} \: b= (2)/(a) ( (3)/(2) - b) = - (2)/(3) \\ \\ (6)/(2a) - (2b)/(a) = - (2)/(3) \\ \\ 6(3) - 2b(6) = 2(2a) \\ 18 - 12b = 4a \\ 12b = 18 - 4a \\ b = (18 - 4a)/(12) \\ \overline{ \underline{\boxed{b = ((9 - 2a))/(6) }}}`

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