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Carlos has \dfrac45 5 4 ​ start fraction, 4, divided by, 5, end fraction of a tank of fuel in his car. He uses \dfrac{1}{10} 10 1 ​ start fraction, 1, divided by, 10, end fraction of a tank per day. How many days will his fuel last? Carlos has \dfrac45 5 4 ​ start fraction, 4, divided by, 5, end fraction of a tank of fuel in his car. He uses \dfrac{1}{10} 10 1 ​ start fraction, 1, divided by, 10, end fraction of a tank per day. How many days will his fuel last? 10

User JayZee
by
5.3k points

2 Answers

1 vote

Answer:

His fuel will last 8 days

Explanation:

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User Abdella
by
5.7k points
0 votes

Answer:

8 days

Explanation:

We are told in the question:

Carlos has 4/5 of a tank of fuel in his car. He uses 1/10 of a tank per day.

How many days will his fuel last?

1/10 of fuel = 1 day

4/5 of fuel = x

Cross Multiply

1/10 × x = 4/5 × 1

x = 4/5 / 1/10

x = 4/5 ÷ 1/10

x = 4/5 × 10/1

x = 8 days

His fuel lasts for 8 days

User Simon GIS
by
4.6k points
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