Question

A cannonball is launched straight upwards with a velocity of vi. If the cannonball reaches a height of 1.25 km, what was the launch speed?

Answer 1

Step-by-step explanation:

2aS=vf^2-vi^2

vf^2=2as+vi^2

vf^2=2*9.8*1.25*10^3+vi^2

vf^2=24500vi2

√vf2=√24500vi2

vf=156.5vi