Question

Use factoring to find the zeros of the following function:
f(x)=5x^3-7x^2-45x+63​

Answer 1

-3, +3, 7/5

Explanation:

(5x³-7x²)+(-45x+63)=0

X²(5x-7)-9(5x-7)=0

(X²+9)(5x-7)=0

Either x²-9=0

X²=9 so x=+3 and -3

Or 5x-7=0

5x=7 so x=1.4 (or 7/5)