Question

A trolley of mass 1 kg travelling at 0.6 m/s receives an impulse of 1.6 kg m/s. What is the new velocity of the trolley?

Answer 1

v₂ = 2.2 [m/s]

Step-by-step explanation:

This problem can be solved using the principle of conservation of momentum and quantity of movement. This problem can be solved using the principle of conservation of momentum and quantity of movement. Where the amount of movement of anybody is equal to the sum of the original moment plus the applied momentum.

`(m_(1)*v_(1))+Imp_(1-2)=(m_(1)*v_(2))`

where:

m₁ = mass of the trolley = 1 [kg]

v₁ = velocity of the trolley before the impulse = 0.6 [m/s]

Imp₁-₂ = Momentum applied = 1.6 [kg*m/s]

v₂ = velocity of the trolley after the impulse [m/s]

`(1*0.6)+1.6=1*v_(2)\\v_(2)=2.2 [m/s]`