Question

Part 1: What is the final volume in milliliters when 0.730 L of a 44.8 % (m/v) solution is diluted to 23.3 % (m/v)?

part 2:A 739 mL NaCl solution is diluted to a volume of 1.50 L and a concentration of 2.00 M . What was the initial concentration?

Answer 1

part 1 : the final volume : 1.404 L

part 2 : the initial concentration : 4.06 M

Further explanation

Dilution is the process of adding a solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution

V₁ = volume of the solution before dilution

M₂ = Molarity of the solution after dilution

V₂ = Molarity volume of the solution after dilution

part 1 :

M₁=44.8%

V₁=0.73 L

M₂=23.3%

`\tt V_2=(M_1.V_1)/(M_2)\\\\V_2=(44.8* 0.73)/(23.3)\\\\V_2=1.404~L`

part 2 :

V₁=739 ml=0.739 L

V₂=1.5 L

M₂=2

`\tt M_1=(M_2.V_2)/(V_1)\\\\M_1=(2* 1.5)/(0.739)\\\\M_1=4.06`