Answer:
The least number of items to produce is 41
Explanation:
Average Cost
Given C(x) as the cost function to produce x items. The average cost is:
![\displaystyle \bar C(X)=(C(x))/(x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/48kd5fswuygrmusukv3zm9qvnb6i4lxjsm.png)
The cost function is:
![C(x) = -20x+1681](https://img.qammunity.org/2021/formulas/mathematics/high-school/t9j54n1enuyvbof18t3lsx8bb9l2vmr2qi.png)
And the average cost function is:
![\displaystyle \bar C(X)=(-20x+1681)/(x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/kj3nmyfspr66qvkcs264onpi9rtguizrk5.png)
We are required to find the least number of items that can be produced so the average cost is less or equal to $21.
We set the inequality:
![\displaystyle (-20x+1681)/(x)\le 21](https://img.qammunity.org/2021/formulas/mathematics/high-school/k0wwkd6e4i4esws0kus4rllj84x8qlj9nl.png)
Multiplying by x:
![-20x+1681 \le 21x](https://img.qammunity.org/2021/formulas/mathematics/high-school/o4pto1q76hzrsqwcv3w8ii6vvcihf2iebz.png)
Note we multiplied by x and did not flip the inequality sign because its value cannot be negative.
Adding 20x:
![1681 \le 21x+20x](https://img.qammunity.org/2021/formulas/mathematics/high-school/fr467uh7l60r6iqjcg77baj09utig8jl7d.png)
![1681 \le 41x](https://img.qammunity.org/2021/formulas/mathematics/high-school/cp9brji0gjfxq20ywb61va744hx8sha8qv.png)
Swapping sides and changing the sign:
![41x \ge 1681](https://img.qammunity.org/2021/formulas/mathematics/high-school/consy7e23wprnsd3lzry3mfllautzas8l8.png)
Dividing by 41:
![x\ge 41](https://img.qammunity.org/2021/formulas/mathematics/high-school/s5l2v2gd1chehvcb6q1pqb626ee5akocxx.png)
The least number of items to produce is 41