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The intensity,I, of light received at a source varies inversely as the square of the distance, d, from the source. If the light intensity is 33 foot-candles at 20 feet, find the light intensity at 5fee

User Violette
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5 votes

Answer:

The light intensity is 528 foot-candles at 5 feet

Explanation:

If x and y are in inverse variation, then x y = k, where k is the constant of variation

In the given question

∵ The intensity I, of light received at a source, varies inversely as the

square of the distance d, from the source

→ That means I × d² = k, where k is the constant of variation

I × d² = k

I = 33 foot-candle at d = 20 feet

→ Substitute them in the rule above to find k

33 × (20)² = k

∴ 33 × 400 = k

13200 = k

→ Substitute the value of k in the equation

I × d² = 13200 ⇒ equation of variation

d = 5

→ Substitute it in the equation to find I

∵ I × (5)² = 13200

∴ I × 25 = 13200

→ Divide both sides by 15

I = 528

The light intensity is 528 at 5 feet

User Nanocv
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