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1 vote
A natural number is multiplied by itself. Is it possible to have 66 at the rightmost end?

1 Answer

5 votes
simple logic for this is :-

for example

11*11=121 (11 is 2 one’s so from 1 till 2 and back )

111*111 =12321 (111 is 3 one’s so count from 1 till 3 and back ) that is 1 2 3 and back 2 1

similarly for 12345678987654321 =111,111,111(9 one’s) *111,111,111
User Corey Sutton
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