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I think I have the slope but I need help with the equation and the y-intercept

I think I have the slope but I need help with the equation and the y-intercept-example-1
User Sowmya
by
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1 Answer

5 votes

Answer:


  • m=(1)/(2)
  • The y-intercept (b) = -2
  • The equation of the line is:


y=(1)/(2)x-2

Explanation:

Given the points

  • (4, 0)
  • (0, -2)

Finding the slope between two points


\mathrm{Slope}=(y_2-y_1)/(x_2-x_1)


\left(x_1,\:y_1\right)=\left(4,\:0\right),\:\left(x_2,\:y_2\right)=\left(0,\:-2\right)


m=(1)/(2)

We know that the y-intercept can be obtained by setting the value x=0 and solving for y.

From the graph, it is clear that at x=0, the value of y = -2

Thus, the y-intercept (b) = -2

We know that the slope-intercept form of the line equation is


y=mx+b

where m is the slope and b is the y-intercept.

Substituting m=1/2 and y-interept (b) = -2 in the slope-intercept form of the line equation


y=mx+b


y=(1)/(2)x+\left(-2\right)


y=(1)/(2)x-2

Thus, the equation of the line is:


y=(1)/(2)x-2

User Scott Kurz
by
7.3k points

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