Question

find two consecutive even integers such that five times the first integer is equal to four times the second integer​

Answer 1

8 and 10

Explanation:

All you need to know to begin setting this up is that to get from one even integer to the next consecutive even integer, add 2.

Start with x = an even integer (yes, because you say so!)

Next even integer = x + 2

"five times the first integer is equal to four times the second integer"

5x = 4(x + 2)

Distribute the 4.

5x = 4x + 8

Subtract 4x

x = 8

The two integers are 8 and 10

5(8) = 4(10) as desired!

Answer 2

8 and 10

Explanation:

"Five times the first is equal to 4 times the second" means the ratio of the smaller to larger is 4 : 5.

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Those ratio units differ by 1. You want two numbers that differ by 2, so you can get them by multiplying these ratio values by 2:

4 : 5 = 8 : 10

Your two numbers are 8 and 10.