Answer:
There are 10 nickels and 11 quarters in the jar.
Explanation:
Given that:
Total coins = 21
Total value = $3.25 = 3.25*100 = 325 cents
One nickel = 5 cents
One quarter = 25 cents
Let,
x be the number of nickels
y be the number of quarters
According to given statement;
x+y=21 Eqn 1
5x+25y=325 Eqn 2
Multiplying Eqn 1 by 5
5(x+y=21)
5x+5y=105 Eqn 3
Subtracting Eqn 3 from Eqn 2
(5x+25y)-(5x+5y)=325-105
5x+25y-5x-5y=220
20y=220
Dividing both sides by 20
![(20y)/(20)=(220)/(20)\\y=11](https://img.qammunity.org/2021/formulas/mathematics/high-school/ybxb1whekk1aszupt8u5p37z4194jwfrsm.png)
Putting y=11 in Eqn 1
x+11=21
x=21-11
x=10
Hence,
There are 10 nickels and 11 quarters in the jar.