Question

The quadratic expression -2k^2+7-5 will equal zero when K is
need help with this quick

Answer 1

Answer: k must be 5/2 or 1

Explanation:

`{ \tt{ - {2k}^(2) + 7k - 5 = 0}}`

» Factorise the equation:

`{ \tt{ {2k}^(2) - 7k + 5 = 0 }} \\ { \tt{(2k - 5)(k - 1) = 0}} \\ \\ { \tt{k = (5)/(2) \: and \: 1 }}`