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Find the equation of a line which passes through point (-1,5) and is parallel
to 3x + y = -12

2 Answers

5 votes

Answer: y = -3x + 2

(please refer to the documents I have uploaded to get a better understanding)

Find the equation of a line which passes through point (-1,5) and is parallel to 3x-example-1
Find the equation of a line which passes through point (-1,5) and is parallel to 3x-example-2
Find the equation of a line which passes through point (-1,5) and is parallel to 3x-example-3
Find the equation of a line which passes through point (-1,5) and is parallel to 3x-example-4
User BStadlbauer
by
7.8k points
6 votes

Answer:

3x + y = 2

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

3x + y = - 12 ( subtract 3x from both sides )

y = - 3x - 12 ← in slope- intercept form

with slope m = - 3

• Parallel lines have equal slopes , then

y = - 3x + c ← is the partial equation

to find c substitute (- 1, 5 ) into the partial equation

5 = 3 + c ⇒ c = 5 - 3 = 2

y = - 3x + 2 ← equation in slope- intercept form

add 3x to both sides )

3x + y = 2 ← equation in standard form

User Dmitry Semenyuk
by
7.8k points

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