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assume that x and y are both differentiable functions of t and find rhe required values of dy/dt and dx/dt. xy=4. find dy/dt, given x=2 and dx/dt =10

User The Matt
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1 Answer

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Differentiate both sides with respect to
t, using the product and chain rules on the left side.


xy = 4 \implies x(dy)/(dt) + y (dx)/(dt) = 0

When
x=2, the given equation tells us that
2y=4\implies y=2. Then if
(dx)/(dt)=10, it follows that


2(dy)/(dt) + 2*10 = 0 \implies (dy)/(dt) = \boxed{-10}

User Catrice
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