Question

a rectangle has a perimeter of 22 feet. the width is 5 feet less than the length. find the length and width of the rectangle​

Answer 1

the length is 8ft

the width is 3ft

Explanation:

Step one:

given

perimter= 22ft

let the length be x

width = x-5

Step two

the expression for the perimeter of a rectangle is

P=2L+2W

substituting our data

22= 2(x)+2(x-5)

open brackets

22=2x+2x-10

collect terms and solve for x

22+10=4x

32=4x

divide both sides by 4

x= 32/4

x= 8ft

the length is 8ft

the width = x-5= 8-5= 3ft