We can set up an equation using the values we know.
We are given the area of the path and pool combined, as well as the side lengths we would use to find that area.
So;
(8+2x)(20+2x)=1120
Now you would solve to find the value of x that makes this equation true.
You should get x=10
Let’s plug that back in and check if it equals the given number.
(8+2(10))(20+2(10))
(8+20)(20+20)
28x40
1120
Yes 1120 matches the value we are given.
So x=10
The width of the path is given to equal x, so the paths width is 10.