Answer:
1225.58 joule
Step-by-step explanation:
Given mass= 0.368 kg
Initial temperature (T1)= 23.8 degree
Final temperature (T2)= 60.00 degree
Change in temperature(ΔT) T2-T1 = 60.00-23.8 = 36.2 degree celsius
S.H.C of copper= 0.0920 cal/gm
= 0.0920 x 1000=92 j/kg degree celsius
now
heat required=MSΔT
0.368 X 92 X 36.2 = 1225.58 JOULE