Question

Graph a parabola whose vertex is at (3, 5) with y-intercept at y= 1

Answer 1

Explanation:

Substituting into vertex form, the equation is:

y = a(x-3)^2 + 5

The y-intercept is when x=0, so substituting this in,

1=a(0-3)^2 + 5

-4 = 9a

a=-4/9