Final answer:
The power of a lightbulb that uses 110V and draws 0.5A is 55 watts, calculated using the formula P = V × I, where P is power, V is voltage, and I is current.
Step-by-step explanation:
The power of a lightbulb that uses 110V and draws 0.5A can be determined by using the formula for electric power, which is P (power) = V (voltage) × I (current). In this case, the voltage V is 110 volts, and the current I is 0.5 amperes. The power P of the lightbulb can be calculated as follows:
P = V × I
P = 110V × 0.5A
P = 55 watts
This means that the lightbulb has a power rating of 55 watts. Remember, this calculation assumes that the given voltage and current are the effective or RMS values, which is typical for AC (alternating current) circuits in household power systems.