Question

What mass of propane could burn in 48.0 g of oxygen?
C3H3 + 502
3CO, + 4H2O

Answer 1

Step-by-step explanation:

mass of 5 mole of oxygen=5*32=160 g

mass of propane =39 g

39 g of propane burn in 160 g of oxygen

so x g could burn in 48.0 g of oxygen=x*160=39*48.0

x=1872/160=11.7 g

therefore 11.7 g of propane could burn in 48.0 g of oxygen