Answer:
The average force exerted on the bullet while it is being accelerated is 6,522.52 N.
Step-by-step explanation:
Given;
mass of the bullet, m = 23 g = 0.023 kg
length of the barrel, L = 62 cm = 0.62 m
speed of the bullet, v = 593 m/s
Applying work-energy theorem;
the work done in accelerating the bullet in the riffle = kinetic energy acquired by the bullet.
W = K.E
F x d = ¹/₂mv²
where;
d is the is the distance traveled by the bullet in the riffle = L
F(0.62) = ¹/₂ x 0.023 x (593²)
F(0.62) = 4043.964
F = (4043.964) / (0.62)
F = 6,522.52 N
Therefore, the average force exerted on the bullet while it is being accelerated is 6,522.52 N.