Answer:
Feed rate F = 625 kg/h
Step-by-step explanation:
Given that:
percentage mass of the solids = 7% = 0.07
rate of removal of water W = 500 kg/h
Concetration C = 35% = 0.35
To fine the feed rate = ???
Using the Overall balance equation,
Suppose: F = W + C
F = 500 + C ---- (1)
Then, the Solids balance can be computed as:
(0.07)F = (0)500 + (0.35)C
0.07F = 0.35C
C = 0.07F/0.35
C = 0.2F
Now
F = 500 + 0.2F
Collect like terms
F – 0.2F = 500
0.8F = 500
F = 500/0.8
F = 625 kg/h
Therefore, the feed rate F = 625 kg/h