Answer:
gₓ = 23.1 m/s²
Step-by-step explanation:
The weight of an object is on the surface of earth is given by the following formula:
![W = mg](https://img.qammunity.org/2021/formulas/physics/college/ohssc86z5xmzwphq7awi5lnljfh0so5ies.png)
where,
W = Weight of the object on surface of earth
m = mass of object
g = acceleration due to gravity on the surface of earth = strength of gravity on the surface of earth
Similarly, the weight of the object on Jupiter will be given as:
![W_(x) = mg_(x)](https://img.qammunity.org/2021/formulas/physics/high-school/zesotclb18clt7ed02ijfqqemxydy0qm8k.png)
where,
Wₓ = Weight of the object on surface of Jupiter = 34.665 N
m = mass of object = 1.5 kg
gₓ = acceleration due to gravity on the surface of Jupiter = strength of gravity on the surface of Jupiter = ?
Therefore,
![34.65 N = (1.5 kg)g_(x)](https://img.qammunity.org/2021/formulas/physics/high-school/1jdfgs7jpmxgjj5wfrp3tsxu9wl80ua4pv.png)
![g_(x) = (34.65 N)/(1.5 kg)](https://img.qammunity.org/2021/formulas/physics/high-school/lonjo0697fmm4npwotis6brqmlirsk4tir.png)
gₓ = 23.1 m/s²