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What is the minimum number of 20-amp 277-volt branch circuits required where 810 incandescent luminaires are to be installed

User Radek Pech
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1 Answer

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Complete Question

What is the minimum number of 20-amp 277-volt branch circuits required where 810 incandescent luminaries are to be installed?The lamps to be installed are rated 75 watts at 277 volts. This is NOT a continuous load so each circuit can carry 20 amps maximum

Answer:

The number is
k = 11

Step-by-step explanation:

From the question we are told that

The current is
I = 20 \ A

The voltage is
V = 277 \ volt

The power rating of each bulb is
P = 75 \ W

The total number of incandescent luminaries is
n = 810

Generally the amount of current each lamp takes is mathematically represented as


I_e = (P)/( V)

=>
I_e = (75)/( 277)

=>
I_e = 0.270 \ A

Generally the number of bulb fitting(i.e bulbs ) a 20 A current can supply (i.e the bulbs the branch ) to is


N = (I)/(I_e)

=>
N = (20 )/( 0.270 )

=>
N = 73.86

Generally the number of 20-amp 277-volt branch circuits required is mathematically represented as


k = (n)/(N)

=>
k = (810)/(73.86)

=>
k = 11

User Ianhi
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