Answer:
0.082 M
Step-by-step explanation:
First we calculate the moles of KOH added, by multiplying its volume and concentration:
- 0.22 M * 16 mL = 3.52 mmol KOH
Given that one mole of acid reacts with one mole of base, in the lactic acid sample there were 3.52 acid moles as well.
Finally we divide the acid moles by the volume, to calculate the concentration:
- 3.52 acid moles / 43 mL = 0.082 M