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Se coloca una tuerca con una llave, como muestra la figura, si el brazo r= 30 cm y el torque de apriete recomendado para la fuerza es de 30 Nxm, Cuàl debe ser el valor de la fuerza F aplicada?

User Ncardeli
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1 Answer

2 votes

Answer:

F = 100 N

Step-by-step explanation:

The torque is given by the expression

τ = F x r

where bold letters indicate vectors, the magnitude of this expression is

τ = F r sin θ

In general, when tightening a nut, the force is applied perpendicular to the arm, therefore θ = 90 and sin 90 = 1

τ = F r

F = τ / r

calculate

F = 30 / 0.30

F = 100 N

User Ceekay
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5.9k points