Answer:
45
Explanation:
Given that :
Voucher awarded (x) :
Repair = $50
Lose or destroy = $200
P(x):
Replacement voucher = 5%
Repair voucher = 10%
X ______ 50 ______ 200
P(x) ____ 0.1 _______ 0.05
Expected variance Var(X) :
ΣX²p(x) - E(x) ;
E(x) = Σx*p(x) = (50*0.1) + (200*0.05) = 15
ΣX²p(x) = Σ[(50^2 * 0. 1) + (200^2 * 0.05)] = 250 + 2000 = 2250
Var(X) = 2250 - 15^2 = 2025
Standard deviation = √Var(x)
Standard deviation = √2025
Standard deviation = $45