Question

(1 point) Let f be a periodic function of period 10 such that f(x)=x2 for −5≤x<5. Then the Fourier series of f is

Answer 1

The answer is "
`(25)/(3)`".

Explanation:

please find the complete question in the attached file.

`a_0=(1)/(10)\int^(5)_(x=-5) x^2 dx\\`

`=(1)/(10) ((x^3)/(3))^(5)_(-5)\\\\=(1)/(30)[5^3+5^3]\\\\=(2)/(30)(125)\\\\=(1)/(15) * 125\\\\=(25)/(3)`