Question

The 10-kg lamp is suspended from the

three equal-length cords. Determine its

smallest vertical distance s from the

ceiling if the force developed in any

cord is not allowed to exceed 50 N.

120°

A

600 mm

120°

Answer 1

hello your question is incomplete attached below is the complete diagram

answer : 519 mm

Step-by-step explanation:

Given the conditions it can be said that the cords are symmetric i.e. AD, BD , CD has same value

hence ; DA = DB = DC = 600 mm

Tension in all cords are the same ( T ) = 50 N

lets assume the angle between the cords and the Z-axis is ∅

∑ Fz = 0

3 * T cos ∅ - 10*9.81 = 0

therefore ; ∅ = 49.16°

looking at attached triangle AD0

tan ∅ =
`(600)/(s)`

Hence ; s = 519 mm