Question

There are 14 teams in a basketball league.

Each team plays every other team twice
during the season.
a) Suppose that you want to determine
how many games, in total, are played.
Suggest a simpler problem that you
could solve first.
b) How many games, in total, are played
during the season?​

Answer 1

Explanation:

Given that :

Number of teams = 14

Each team plays every other team twice ;

Using the combination formula :

nCr = n! ÷ (n-r)! r!

14C2 = 14! ÷ (14 - 2)! 2!

14C2 = 14! ÷ (12)! 2!

14C2 = (14 * 13) ÷ 2 * 1

14C2 = 182 / 2

14C2 = 91

Hence, since they are going to be playing each other twice :

2(14C2)

2 * 91 = 182games