Answer:
1.786m/s
Step-by-step explanation:
We are given the following the following
Initial speed u = 0.5m/s
initial distance S1 = 15cm = 0.15m
Final distance = 0m
Required
Final speed v
Using the equation of motion;
v² = u²+2gS
v² = 0.5²+2(9.8)(0.15)
v² = 0.25+2.94
v² = 3.19
v = √3.19
v = 1.786m/s
Hence its speed when it reaches the bottom is 1.786m/s