Question

A solenoid that is 133 cm long has a radius of 2.99 cm and a winding of 1740 turns; it carries a current of 3.91 A. Calculate the magnitude of the magnetic field inside the solenoid.

Answer 1

The value is
`B = 0.0643 \ T`

Step-by-step explanation:

From the question we are told that

The length of the solenoid is
`L = 133 \ cm = 1.33 \ m`

The radius is
`r = 2.99 \ cm = 0.0299 \ m`

The number of turns is
`N = 1740 \ turns`

The current it carries is
`I = 3.91 \ A`

Generally the magnitude of the magnetic field is mathematically represented as

`B = (\mu_o * N * I)/(L)`

Here
`\mu_o` is the permeability of free space with value
`\mu_o = 4\pi *10^(-7) \ N/A^2`

=>
`B = ( 4\pi * 10^(-7) * 1740 * 3.91)/(0.133)`

=>
`B = 0.0643 \ T`