Question

A 5.0 Newton force is applied to the right of a 6.0 kg object to move across a smooth surface. The coefficient of friction is zero. a. Draw and label all of the forces acting on the object b. Calculate the acceleration of the object

Answer 1

`0.833\ \text{m/s}^2`

Step-by-step explanation:

m = Mass of block = 6 kg

F = Force on block = 5 N

`\mu` = Coefficient of friction = 0

a = Acceleration of the block

From Newton's second law we have

`F=ma\\\Rightarrow a=(F)/(m)\\\Rightarrow a=(5)/(6)\\\Rightarrow a=0.833\ \text{m/s}^2`

The acceleration of the block is
`0.833\ \text{m/s}^2`