Question

A student carefully placed 18.1 g of sodium in a reactor supplied with an excess quantity of chlorine gas. When the reaction was complete, the student obtained 39.6 g of sodium chloride. How many grams of chlorine gas reacted?

Answer 1

The mass of chlorine gas that reacted ≅ 24.03 g

Step-by-step explanation:

From the given information:

The number of moles of NaCl formed = mass of NaCl/molar mass

mass of NaCl = 39.6 g

molar mass = (23 + 35.5) g/mol = 58.5 g/mol

∴

The number of moles of NaCl formed = 39.6 g / 58.5 g/mol

The number of moles of NaCl formed = 0.6769 g/mol

Thus, the mass of chlorine gad that reacted = 0.6769 × 35.5

The mass of chlorine gas that reacted = 24.02995 g

The mass of chlorine gas that reacted ≅ 24.03 g