Answer:
41/40
Explanation:
Given cotA = 40/9
1/tanA = 40/9
tanA = 9/40
According to SOH, CAH, TOA
tan A = 9/40 = opposite/adjacent
Get the hypotenuse
hyp² = opp²+adj²
hyp² = 9²+40²
hyp² = 81+1600
hyp² = 1681
hyp = √1681
hyp = 41
Het sec A
sec A = 1/cosA
Since cos A = adjacent/hypotenuse
cos A = 40/41
secA = 1/(40/41)
SecA = 41/40
Hence the exact value of secA is 41/40