Question

What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor

Answer 1

Complete Question

A 8.0 A current is charging a 1.0 -cm-diameter parallel-plate capacitor. What is the magnetic field strength at a point 2.5 mm radially from the center of the wire leading to the capacitor?

Answer:

The magnetic field is
`B = 6.4*10^(-4) \ T`

Step-by-step explanation:

From the question we are told that

The current is
`I = 8.0 \ A`

The diameter is
`d = \ cm = (1)/(100) = 0.01 m`

The position considered is
`d = 2.5 \ mm = 0.0025 \ m`

Generally the magnetic field is mathematically represented as

`B = (\mu_o * I )/( 2 \pi d)`

Here
`\mu_o` is permeability of free space with value

`\mu_o = 4\pi * 10^(-7) \ N/A^2`

So

`B = ( 4\pi * 10^(-7) * 8 )/( 2 \pi * 0.0025 )`

=>
`B = ( 2 * 10^(-7) * 8 )/( * 0.0025 )`

=>
`B = 6.4*10^(-4) \ T`