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g calculate the effectiveness radiation dosage in sieverts for a 79 kg person who is exposed 6.8x10^9

User Hiropon
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2 votes

Answer:

The answer is "
\bold{dosage = 0.031 rem}"

Step-by-step explanation:

please find the complete question in the attached file.

Given value:


m = 79\ kg \\\\n = 3.4 * 10^9 \\\\E = 5.5 * 10^(-13) \\\\ RBE = 15


\to E = n E\\


= 3.4 * 10^9 * 5.5 * 10^(-13) \\\\ = 1.87 * 10^(-3)


\to E(absorbed) = 1.87 * 10^(-3) * 0.87 = 1.63 * 10^(-3)

calculating the radiation absorbed per kg:


= (1.63 * 10^(-3))/(79) \\\\ = 2.06 * 10^(-5) \\\\ = 0.00206 \ rad


\to Dosage = 0.00206 * 15 \\


= 0.031 \ \ rem

g calculate the effectiveness radiation dosage in sieverts for a 79 kg person who-example-1
User Protongun
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