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Find an equation of the line passing through the points
(–3, –5) and (6, –2).

User Eric Tsui
by
8.8k points

2 Answers

6 votes

Answer: y=1/3x-4

Step-by-step explanation:

Begin by finding the slope of the line. You can do this by using the given ordered pairs and plugging them into the slope formula, y^2-y^1/x^2-x^1. Plugging them would appear as -2-(-5)/6-(-3). The resulting math would be 3/9 or 1/3 when simplified. Using the slope-intercept form, we can plug in the slope to make it y=1/3x+b. Choose any ordered pair to plug into the equation. I'm going to use (-3,-5). Plugging this in would result with -5=1/3(-3)+b. Multiply 1/3 and -3 to get -5=-1+b. Add -1 to both sides to get b=-4.

User Dean Friedland
by
8.5k points
2 votes

Answer:

y=1/3x-4

Step-by-step explanation:

1. Use the slope formula to find the slope of the two coordinates.

y2-y1/x2-x1

-2--5/6--3

3/9 = 1/3

The slope is 1/3

2. Choose one of the coordinates and plug them and the slope into the point-slope formula

y-y1=m(x-x1)

y+2=1/3(x-6)

3. Distribute and simplify.

y+2=1/3x-2

y=1/3x-4

User XeroxDucati
by
7.4k points

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