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24 votes
24 votes
A1=10an=an-1+4 ??????? help pls

User TML
by
2.8k points

1 Answer

20 votes
20 votes

I assume you're asked to solve for
a_n, or find an explicit formula for the n-th term in the sequence.

The sequence is recursively defined by


\begin{cases} a_1 = 10 \\ a_n = a_(n-1) + 4 & \text{for } n \ge 1 \end{cases}

By this definition,


a_(n-1) = a_(n-2) + 4

so that by substitution,


a_n = (a_(n-2) + 4) + 4 = a_(n-2) + 2*4

and we can repeat this process to find


a_n = a_(n-3) + 3*4


a_n = a_(n-4) + 4*4

and so on, down to


a_n = a_1 + (n-1)*4

Then given the first term
a_1=10, we have


a_n = 10 + 4(n-1) \implies \boxed{a_n = 4n + 6}

User Ryan Norooz
by
3.4k points
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