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what is the average rate of change of the equation: y=4x^2-10x+2, between f(3) and f(5)? ​

User Nategoose
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1 Answer

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Answer:

Average rate of change=22

Explanation:

We need to find the average rate of change of the equation:
y=4x^2-10x+2between f(3) and f(5).

The formula used to find average rate of change is:
Average \ rate \ of \ change=(f(b)-f(a))/(b-a)

In the given question we have a=3 and b =5

Finding f(a) i.e f(3)


f(3)=4(3)^2-10(3)+2\\f(3)=4(9)-30+2\\f(3)=36-30+2\\f(3)=8

Finding f(b0 i.e f(5)


f(5)=4(5)^2-10(5)+2\\f(5)=4(25)-50+2\\f(5)=100-50+2\\f(5)=52

Putting values of f(3)=8 and f(5)=52 to find average rate of change


Average \ rate \ of \ change=(f(b)-f(a))/(b-a)\\Average \ rate \ of \ change=(52-8)/(5-3)\\Average \ rate \ of \ change=(44)/(2)\\Average \ rate \ of \ change=22

So, Average rate of change=22

User ThanhHH
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