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A compound is made of 36.36% C, 7.13% H, 56.51% O. What is its empirical formula?

User Eli Y
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Its empirical formula : C₅H₁₂O₆

Further explanation

The empirical formula is the smallest comparison of atoms of compound forming elements.

(empirical formula) n = molecular formula

The principle of determining empirical formula and molecular formula

  • Determine the mass ratio of the constituent elements of the compound.
  • Determine the mole ratio by dividing the elemental mass with the relative atomic mass obtained by the empirical formula

Ar C = 12 g/mol

Ar H = 1 g/mol

Ar O = 16 g/mol

mol ratio of C : H : O =


\tt (36.36)/(12)/ (7.13)/(1)/ (56.51)/(16)\\\\3.03/ 7.13/ 3.53\rightarrow divided~by~smallest(3.03)\\\\1/ 2.4/ 1.2(* 10)\rightarrow 5/ 12/ 6

User Udara Herath
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