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Find the 32nd term if a4=3 and a20 =35

User Juned
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1 Answer

10 votes

Answer:

a32 = 59

Explanation:

arithmetric sequence

first find the common difference

20 - 4 = 16

a20=a4+16d

35=3+16d

32=16d

2=d

d=2

common difference is 2

an = a1 + (n – 1)d

a20=a1+(20-1)2

35=a1+(19)2

35=a1+38

-3=a1

a1= -3

first term is -3

32nd term

a32 = -3 + (31)2

a32 = -3 + 62

a32 = 59

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