Question

Through(-2,-3); parallel to 3x+2y=5

Answer 1

Hopefully it this helps.

Answer 2

Explanation:

Hey there!

Firstly find slope of the given equation.

Given eqaution is: 3x + 2y = 5.......(i)

Now;

`slope(m1) = ( - coeff. \: of \: x)/(coeff. \: of \: y)`

`or \: m1 = ( - 3)/(2)`

Therefore, slope (m1) = -3/2.

As per the condition of parallel lines,

Slope of the 1st eqaution (m1) = Slope of the 2nd eqaution (m2) = -3/2.

The point is; (-2,-3). From the above solution we know that the slope is (-3/2). So, the eqaution of a line which passes through the point (-2,-3) is;

(y-y1) = m2 (x-x1)

~ Keep all values.

`(y + 3) = ( - 3)/(2) (x + 2)`

~ Simplify it.

`2(y + 3) = - 3x - 6`

`2y + 6 = - 3x - 6`

`3x + 2y + 12 = 0`

Therefore, the eqaution of the line which passes through the point (-2,-3) and parallel to 3x + 2y= 5 is 3x + 2y +12 =0.

Hope it helps...