Question

A person throws a pumpkin at a horizontal speed of 4.0 m/s off a cliff. The pumpkin travels 9.5m horizontally before it hits the ground.

Answer 1

The pumpkin's vertical displacement is H=27.76m

The pumpkin's vertical velocity when it hits the ground is v=23.32m/s

Step-by-step explanation:

x=v*t

9.5=4*t

t=2.38s

H=vi(t)+1/2at^2

H=1/2at^2

H=1/2(9.8)(2.38)^2=27.76

vf=vi+at

vf=2.38(9.8)

vf=23.32m/s