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(x+26=y) and (y-12=z) if x+y+z=71 solve for x

User Malenko
by
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1 Answer

9 votes

Answer:


\mathsf{x = (31)/(3)}

Explanation:


\textsf {Given :}


\implies \mathsf {x + 26 = y}


\implies \mathsf {y - 12 = z}


\implies \mathsf{x + y + z = 71}


\textsf {Substitute for y and z in the 3rd equation :}


\implies \mathsf {x + x + 26 + y - 12 = 71}


\implies \mathsf {2x + 14 + x + 26 = 71}


\implies \mathsf {3x + 40 = 71}


\implies \mathsf {3x = 31}


\implies \mathsf {x = (31)/(3)}

User Zpavlinovic
by
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