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Need help once again!

Need help once again!-example-1
User Anteo
by
6.4k points

1 Answer

4 votes

Answer:

θ = cos-1 (38/47)

Explanation:

sin θ =
(opposite)/(hypotenuse) = (27)/(47)\\

θ = sin-1 (27/47)

cos θ =
(adjacent)/(hypotenuse) = (38)/(47)

θ = cos-1 (38/47)

tan θ =
(opposite)/(adjacent) = (27)/(38)

θ = tan-1 (27/38)

User Mardzis
by
6.5k points
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